Calcoliamo i seguenti quadrati di binomio, applicando
$(\color{blue}A+\color{green}B)^2 = \color{blue}A^2 + 2\color{blue}A\color{green}B + \color{green}B^2$.
$(\color{blue}{7a} + \color{green}{3b})^2 = $
$(\color{blue}{7a})^2 + 2 \cdot \color{blue}{7a} \cdot \color{green}{3b} +
(\color{green}{3b})^2 =$
$49a^2 + 42ab + 9b^2 $
$(x^3 - 5)^2 = [\color{blue}{x^3} + (\color{green}{-5})]^2 =$
$(\color{blue}{x^3})^2 + 2 \cdot \color{blue}{x^3} \cdot (\color{green}{-5}) +
(\color{green}{-5})^2 =$
$x^6 - 10x^3 + 25 $
$(\color{blue}{-a} \color{green}{-1})^2 =$
$(\color{blue}{-a})^2 + 2 \cdot (\color{blue}{-a}) \cdot (\color{green}{-1}) +
(\color{green}{-1})^2 = $
$a^2 + 2a + 1$